Question

Oxidation number of O in $~{{O}_{3}}$ is:
(A) +1
(B) -1
(C) 0
(D) +2
(E) +3

Answer 1

Hint: To answer this question we should know that oxidation number represents the number of electrons that an atom can gain, lose, or share it chemically form a bond with an atom of another element.

Complete step by step solution:

To answer this question, we should first know about oxidation state. We should know that an oxidation state is a number. Oxidation number assigned to an element in a chemical combination. This number shows the number of electrons that an atom can gain, lose, or share when it is chemically bonded with an atom of another element.
There are some rules that we should know about oxidation state.
- Rule 1: we should know that an individual atom which remains un-combined with another element has the oxidation state of zero.
We can understand by this one example, we should remember that the oxidation state of Ag is zero. If we take the example of oxygen, the oxidation state of O (oxygen) will be zero in$~{{O}_{2}}$ is 0 as long as it is un-combined with any other element.
- We can use this above rule in determining the oxidation state of O in$~{{O}_{3}}$. We know from that $~{{O}_{3}}$ is not in a combined state with other elements. And from the above rule we know that if any element is not in combined state with any other element, its oxidation state will be zero. So, answer of this question option C.

Note: There are other rules as well for determination of oxidation state in other types of compounds. We should note that the sum of all atoms in a given species is equal to net charge on that compound. In a neutral compound, the sum of all atoms will be equal to zero. And in ionic compounds, it is equal to charge on that ion.