Question

Oxidation number of $N$ is $HN{{O}_{3}}$ is

• A. -3.5
• B. 3.5
• C. - 3,+ 5
• D. 5

Answer 1

Answer: (D)

5

Answer 2

Let the oxidation state of $N$ in $HN{{O}_{3}}=x$ $\therefore$ $+ 1+x+(-2\times 3)=0$ Or $x+1-6=0$ $\therefore$ $x=+5$