Question

Oxidation number of N in$\left( NH_{4} \right)_{2}SO_{4}$ is

• A. –1/3
• B. – 1
• C.
  • 1
• D. – 3

Answer 1

Answer: (D)

– 3

Answer 2

$\left( NH_{4} \right)_{2}SO_{4}$ ⇌ $2\underline{N} ⥂ H_{4}^{+} + SO_{4}^{- 2}$

$\underline{N} ⥂ H_{4}^{+}$

$x + 4 = + 1$ or $x = 1 - 4 = - 3$