Oxidation number of ( N ) in ( NH\_{3}) (hydrazoic acid) is:... | Chemistry | SolveeIt | Solveeit

Today, August 18

Question

Oxidation number of $N$ in $NH_{3}$ (hydrazoic acid) is:

A

$-\frac{1}{3}$

B

$+3$

C

$0$

D

$-3$

Answer

$-\frac{1}{3}$

Explanation

Solution

$N _{3} H$ (hydrozoic acid) $+3(x)+1 =0$ $3 x+1 =0$ $x =-\frac{1}{3}$