Question
Chemistry Question on Redox reactions
Oxidation number of Mo in Ammonophosphomolybdate
Answer
(NH4)3PMo12O40 or (NH4)3PO4.12MoO3
+3 + 5 +12x – 80 = 0
12x = 80 – 8
12x = 72
x = 6
So, the oxidation number of Mo is 6
Oxidation number of Mo in Ammonophosphomolybdate
(NH4)3PMo12O40 or (NH4)3PO4.12MoO3
+3 + 5 +12x – 80 = 0
12x = 80 – 8
12x = 72
x = 6
So, the oxidation number of Mo is 6