Oxidation number of iodine in (IO\_{3}^{-},IO\_{4}^{-},) KI... | CHEMISTRY - OXIDATION NUMBER | SolveeIt

Oxidation number of iodine in $IO_{3}^{-},IO_{4}^{-},$ KI and $I_{2}$ respectively is.

$- 2, - 5 - 1,0$

$+ 5, + 7, - 1,0$

$+ 2, + 5, + 1,0$

$- 1, + 1,0, + 1$

Answer

$+ 5, + 7, - 1,0$

Explanation

: $IO_{3}^{-} \rightarrow x + 3( - 2) = - 1 \Rightarrow x = + 5$

$IO_{3}^{-} \rightarrow x + 4( - 2) = - 1 \Rightarrow x = + 7$

$KI \rightarrow + 1 + x = 0 \Rightarrow x = - 1$

$I_{2} \rightarrow 0 \Rightarrow x = 0$

Question: Oxidation number of iodine in \(IO_{3}^{-},IO_{4}^{-},\) KI and \(I_{2}\) respectively is....