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Chemistry Question on Oxidation Number

Oxidation number of iodine in IO3−IO_3^-, IO4−IO_4^-, KIKI and I2I_2 respectively is

A

-2, -5, -1, 0

B

#ERROR!

C

#ERROR!

D

- 1, +1, 0, +1

Answer

#ERROR!

Explanation

Solution

IO3−→x+3(−2)=−1⇒x=+5IO_{3}^{-} \to x + 3\left(-2\right) = -1 \Rightarrow x = + 5 IO4−→x+4(−2)=−1⇒x=+7IO_{4}^{-} \to x + 4\left(-2\right) = -1 \Rightarrow x = +7 KI→+1+x=0⇒x=−1KI \to + 1 + x = 0 \Rightarrow x = -1 I2→0⇒x=0I_{2} \to 0 \Rightarrow x = 0