Question

Oxidation number of $Cl$ in $NOClO_4$ is

• A. 7
• B. -7
• C. 5
• D. -5

Answer 1

Answer: (A)

7

Answer 2

Calculate oxidation number of $Cl$ in $NOClO_4$ by assuming $ClO_4^ -$ and $NO^+$. Oxidation number of oxygen is $-2$, then oxidation number of chlorine in $ClO_4^ -$ is $x + 4$(oxidation number of oxygen) $= -1$ $x + 4(-2) = -1 ?$?