Question

Oxidation number of carbon in $CH_{2}Cl_{2}$ is

• A. 0
• B. +1
• C. +2
• D. +4

Answer 1

Answer: (A)

0

Answer 2

: $CH_{2}Cl_{2} \rightarrow x + 2( + 1) + 2( - 1) = 0 \Rightarrow x = 0$