Question

Oxidation number of carbon in $CH_2Cl_2$ is

• A. $0$
• B. $+1$
• C. $+2$
• D. $+4$

Answer 1

Answer: (A)

$0$

Answer 2

$CH_{2}Cl_{2} \to x + 2\left(+1\right) + 2\left(-1\right) = 0 \Rightarrow x = 0$