Question

Oxidation number $Fe$ in $K_{3}[Fe(CN)_{6}]$ is:

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

Answer: (C)

3

Answer 2

Let, oxidation number of $Fe$ be '$x$'.
$\therefore 3\left( +1 \right)+x+6\left( -1 \right)=0$
$3 + x- 6=0$
$x = +\,3$