Question

Oxidation number $Fe$ in ${{K}_{3}}[Fe{{(CN)}_{6}}]$ is:

• A. $+1$
• B. $+2$
• C. $+3$
• D. $+4$

Answer 1

Answer: (C)

$+3$

Answer 2

Let, oxidation number of $Fe$ be $x$ . $\therefore$ $3(+1)+x+6(-1)=0$ $3+x-6=0$ $x=+3$