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Question: Out of a total distance of \(200\,km\) covered, the first half is covered at the speed of \(60\,km/h...

Out of a total distance of 200km200\,km covered, the first half is covered at the speed of 60km/hr60\,km/hr and the remaining half is covered at 75km/hr75\,km/hr. Find the average speed for the whole journey.
A. 212321\dfrac{2}{3} km/hr
B. 662366\dfrac{2}{3} km/hr
C. 432343\dfrac{2}{3} km/hr
D. 392339\dfrac{2}{3} km/hr

Explanation

Solution

The pace at which an object's location changes in any direction is known as speed. Speed is defined as the ratio of distance travelled to the time it took to travel that distance. Because speed has just one direction and no magnitude, it is a scalar number. The following notion is employed in this instance.

Complete step by step answer:
The magnitude of the rate of change of an item's position with time or the magnitude of change of its position per unit of time is the speed (often referred to as v) of an object in daily use and in kinematics; it is therefore a scalar number. The average speed of an object in a given time interval is the item's distance travelled divided by the period's duration; the instantaneous speed is the average speed's limit as the interval's duration approaches zero.

Speed= Distance  Time \text{Speed} = \dfrac{{{\text{ Distance }}}}{{{\text{ Time }}}}
AverageSpeed= Total Distance Travelled  Total Time Taken \Rightarrow \text{AverageSpeed} = \dfrac{{{\text{ Total Distance Travelled }}}}{{{\text{ Total Time Taken }}}}
Since 100 Km is covered at 60 km/hr.Time,
t1= Distance  Speed  t1=10060 t1=53h{{\text{t}}_1} = \dfrac{{{\text{ Distance }}}}{{{\text{ Speed }}}} \\\ \Rightarrow {{\text{t}}_1} = \dfrac{{100}}{{60}} \\\ \Rightarrow {{\text{t}}_1} = \dfrac{5}{3}h
And since another 100 km is covered at 75 km/hr. Time,
t2= Distance  Speed  t2=10075 t2=43{{\text{t}}_2} = \dfrac{{{\text{ Distance }}}}{{{\text{ Speed }}}} \\\ \Rightarrow {{\text{t}}_2} = \dfrac{{100}}{{75}} \\\ \Rightarrow {{\text{t}}_2} = \dfrac{4}{3}
So, the total time taken is represented as
t=53+43=3hrt = \dfrac{5}{3} + \dfrac{4}{3} = 3{\text{hr}}
Hence, average speed
AverageSpeed=2003 AverageSpeed=6623  km hr1\text{AverageSpeed} = \dfrac{{200}}{3} \\\ \therefore \text{AverageSpeed}= 66\dfrac{2}{3}\;{\text{km h}}{{\text{r}}^{ - 1}}

Hence, the correct answer is option B.

Note: Make sure you follow the correct unit conversions. The parameters of speed are distance divided by time. The metre per second (m/s) is the SI unit of speed, although the kilometre per hour (km/h) or miles per hour (in the US and the UK) is the most frequent measure of speed in everyday use (mph). The knot is frequently used in aviation and maritime transport.