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Question: Out of 30 consecutive numbers, 2 are chosen at random. The probability that their sum is odd, is...

Out of 30 consecutive numbers, 2 are chosen at random. The probability that their sum is odd, is

A

1429\frac { 14 } { 29 }

B

1629\frac { 16 } { 29 }

C

1529\frac { 15 } { 29 }

D

1029\frac { 10 } { 29 }

Answer

1529\frac { 15 } { 29 }

Explanation

Solution

The total number of ways in which 2 integers can be chosen from the given 30 integers is 30C2{ } ^ { 30 } C _ { 2 } The sum of the selected numbers is odd if exactly one of them is even and one is odd.

\ Favourable number of outcomes = 15C115C1{ } ^ { 15 } C _ { 1 } \cdot { } ^ { 15 } C _ { 1 }

\therefore Required probability =15C115C130C2=1529= \frac { { } ^ { 15 } C _ { 1 } \cdot { } ^ { 15 } C _ { 1 } } { { } ^ { 30 } C _ { 2 } } = \frac { 15 } { 29 }.