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Question

Mathematics Question on Probability

Out of 1515 persons, 1010 can speak Hindi and 88 can speak English. If two persons are chosen at random, then the probability that one person speaks Hindi only and the other speaks both Hindi and English is

A

35 \frac{3}{5}

B

712 \frac{7}{12}

C

15 \frac{1}{5}

D

25 \frac{2}{5}

Answer

15 \frac{1}{5}

Explanation

Solution

Number of persons who can speak Hindi only =158=7= 15-8 = 7 Number of persons who can speak both Hindi and English =10+815=3= 10 + 8 - 15 = 3 Now, probability that one person speaks Hindi only and other speaks both Hindi and English, is 7C1×3C115C2=7×315×142\frac{^{7}C_{1}\times^{3}C_{1}}{^{15}C_{2}} =\frac{ 7\times3}{\frac{15\times14}{2}} =7×3×215×14=15 =\frac{ 7\times3\times2}{15\times14} = \frac{1}{5}