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Question

Mathematics Question on Sets

Out of 100100 students; 1515 passed in English, 1212 passed in Mathematics, 88 in Science, 66 in English and Mathematics, 77 in Mathematics and Science, 44 in English and Science; 44 in all the three passed. Then (i) The number of students passed in English and Mathematics but not in Science is (ii) The number of students only passed in Mathematics is (iii) The number of students passed in more than one subject is

A

a

B

b

C

c

D

d

Answer

b

Explanation

Solution

Let UU, EE, MM and SS be denote the total number of students, number of students passed in English, Mathematics and Science, respectively. Here, n(U)=100n(U) = 100, n(E)=15n(E) = 15, n(M)=12n(M) = 12, n(S)=8n(S) = 8, n(EM)=6n(E \cap M) = 6, n(MS)=7n(M \cap S) = 7, n(ES)=4n(E \cap S) = 4 and n(EMS)=4n (E \cap M \cap S) = 4 (i) \therefore The number of students passed in English and Mathematics but not in Science =n(EMSˉ)= n ( E \cap M \cap \bar{S}) =n(EM)n(EMS)=64=2= n(E \cap M) - n(E \cap M \cap S) = 6 - 4 = 2 (ii) The number of students only passed in Mathematics =n(MEˉSˉ)= n(M \cap \bar{E} \cap \bar{S}) =n(M)n(ME)n(MS)+n(MES)= n(M) - n(M \cap E) - n(M \cap S) + n(M \cap E \cap S) =1267+4=1613=3= 1 2 -6 -7 + 4 = 16-13 = 3 (iii) The number of students passed in more than one subject =n(ME)+n(MS)+n(SE)2n(MES)= n(M \cap E) + n(M \cap S ) + n(S \cap E) - 2n(M \cap E \cap S) =6+7+42(4)=178=9= 6 + 7 + 4 - 2(4) = 17-8 = 9