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Question: Osmotic pressure of a solution containing 2 g dissolved protein per 300 \(cm^{3}\) of solution in 20...

Osmotic pressure of a solution containing 2 g dissolved protein per 300 cm3cm^{3} of solution in 20 mm of Hg at 27ºC27ºC.

The molecular mass of protein is

A

6239.6gmol−16239.6gmol^{- 1}

B

12315.5gmol−112315.5gmol^{- 1}

C

3692.1gmol−13692.1gmol^{- 1}

D

7368.4gmol−17368.4gmol^{- 1}

Answer

6239.6gmol−16239.6gmol^{- 1}

Explanation

Solution

π=nBRTV;nB=WBMB\pi = \frac{n_{B}RT}{V};n_{B} = \frac{W_{B}}{M_{B}}

π=WBMB×RTV\pi = \frac{W_{B}}{M_{B}} \times \frac{RT}{V}

MB=WBV×RTπ=2×0.0821×300×7600.3×20M_{B} = \frac{W_{B}}{V} \times \frac{RT}{\pi} = \frac{2 \times 0.0821 \times 300 \times 760}{0.3 \times 20}

=6239.6gmol−1= 6239.6gmol^{- 1}