Orthocentre of triangle having vertices as A (1,2), B(3,-4),... | Mathematics | SolveeIt | Solveeit

Today, August 19

Question

Orthocentre of triangle having vertices as A (1,2), B(3,-4), C(0,6) is

A

(-129, -37)

B

(9, -1)

C

(7, -3)

D

(28, -16)

Answer

(-129, -37)

Explanation

Solution

Correct answer is (A). (-129, -37)

AD = (y-2)= $\frac{3}{10}$ (x-1)

3x-10y+17=0….(i)

BE = (y+4)= $\frac{1}{4}$ (x-3)

x-4y=19 …..(ii)

solving (i) and (ii),

(-129, -37) is Orthocentre