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Question: Orthocenter of triangle with vertices (0, 0), (3, 4) and (4, 0) is...

Orthocenter of triangle with vertices (0, 0), (3, 4) and (4, 0) is

A

(3,54)\left( 3,\frac{5}{4} \right)

B

(3, 12)

C

(3,34)\left( 3,\frac{3}{4} \right)

D

(3, 9)

Answer

(3,34)\left( 3,\frac{3}{4} \right)

Explanation

Solution

In DAEH

tan q = K3\frac{K}{3} (1)

in DC EB

tan q = 14\frac{1}{4} (2)

by (1) and (2)

\ k3\frac{k}{3}= 14\frac{1}{4}

\ K = 34\frac{3}{4}

\ orthocentre (3,34)\left( 3,\frac{3}{4} \right)