Question

Order of Ka which can be predicted by following reaction is :

$\xrightarrow { \mathrm { NaNH } _ { 2 } }$ $\xrightarrow { \mathrm { C } _ { 2 } \mathrm { H } _ { 2 } } \mathrm { HC } \equiv \mathrm { CNa } + \mathrm { Ph } _ { 3 } \mathrm { CH } \xrightarrow { \mathrm { H } _ { 2 } \mathrm { O } } \mathrm { HC } \equiv \mathrm { CH } + \mathrm { NaOH }$

• A. NH3>Ph3CH > C2H2> H2O
• B. H2O > HC⁰ CH >Ph3CH > NH3
• C. HC⁰ CH > H2O >Ph3CH > NH3
• D. Ph3CH > HC⁰ CH > H2O > NH3

Answer 1

Answer: (B)

H2O > HC⁰ CH >Ph3CH > NH3

Answer 2

On the basis of stability of conjugate base due to electronegativity