Question

Orbital having 3 angular nodes and 3 total nodes is :-

• A. 5 p
• B. 3 d
• C. 4 f
• D. 6 d

Answer 1

Answer: (C)

4 f

Answer 2

Orbital having angular node $(\ell) = 3$ Total node = Radial node + angular node $= n - \ell -1 + \ell$ $3 = n - 1$ $n = 4$ Subshell "$n\ell$" $= 4f$