Question

Orbital angular momentum depends on?

Answer 1

Angular momentum of an electron was given by Bohr. This is the result of applying quantum theory to the orbit of the electron. The solution of the Schrodinger equation yields the angular momentum quantum number.

Complete step-by-step answer: According to Bohr’s atomic model, the angular momentum of electron orbiting around the nucleus is quantized, which is given by
$mvr=\frac{nh}{2\pi }$
Where, m = mass of the electron
n = integer 1,2,3,4…
v = velocity
h = Planck’s constant
r = radius

He also added that electrons move only in those orbits where angular momentum of an electron is an integral multiple of h/2.
His postulates regarding the quantization of angular momentum of an electron was later explained by DE Broglie.
Now, orbital angular momentum is the component of angular momentum. It is the value of angular momentum of the electron revolving around the orbit and the fact that the electron is spinning around its own axis is neglected i.e., the spin is constant.
Orbital angular momentum is $L=\sqrt{l(l+1)h}$
Here, l is the azimuthal quantum number.
The azimuthal quantum number (l) is the quantum number associated with the angular momentum of an atomic electron. It is also known as the angular momentum quantum number or the second quantum or the second quantum number.

Note: The first equation gives the angular momentum of an electron revolving in a circular orbit, for example an electron is present in the fifth orbit. However, orbital angular momentum of electrons in a given orbital, for example an electron is present in d orbital.