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Question: \(\operatorname { Lim } _ { n \rightarrow \infty }\) \(\left\lbrack \frac{1}{1 - n^{4}} + \frac{8}{1...

Lim⁡n→∞\operatorname { Lim } _ { n \rightarrow \infty } [11−n4+81−n4+.....n31−n4]\left\lbrack \frac{1}{1 - n^{4}} + \frac{8}{1 - n^{4}} + .....\frac{n^{3}}{1 - n^{4}} \right\rbrack equals

A

14\frac{1}{4}

B

18\frac{1}{8}

C

12\frac{1}{2}

D

None of these

Answer

None of these

Explanation

Solution

=

= = (1+0)24(0−1)=\frac { ( 1 + 0 ) ^ { 2 } } { 4 ( 0 - 1 ) } = −14- \frac { 1 } { 4 }