Question

Only 2% of the optical source frequency is the available channel bandwidth for an optical communicating system operating at 1000 nm. If an audio signal requires a bandwidth of 8 kHz, how many channels can be accommodated for transmission?

• A. 375 × 107
• B. 75 × 107
• C. 375 × 108
• D. 75 × 109

Answer 1

Answer: (B)

75 × 107

Answer 2

The correct option is(B): 75 × 107

$v=fλ$

⇒ Channels

$\frac{\frac{2}{100}×3×10^{14}}{8×10^3}=75×10^7$