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Question: One weak acid (like\(\text{ C}{{\text{H}}_{\text{3}}}\text{COOH }\)) and its strong base together wi...

One weak acid (like CH3COOH \text{ C}{{\text{H}}_{\text{3}}}\text{COOH }) and its strong base together with salt (like CH3COONa \text{ C}{{\text{H}}_{\text{3}}}\text{COONa }) is a buffer solution. In which pair the type of character is found:
A)  HCl \text{ HCl } and  NaCl \text{ NaCl }
B)  NaOH \text{ NaOH } and  NaNO3 \text{ NaN}{{\text{O}}_{\text{3}}}\text{ }
C)  KOH \text{ KOH } and  KCl \text{ KCl }
D)  NH4OH \text{ N}{{\text{H}}_{\text{4}}}\text{OH } and  NH4Cl \text{ N}{{\text{H}}_{\text{4}}}\text{Cl }

Explanation

Solution

A buffer solution is one that can resist change in its  pH \text{ pH } on the addition of an acid or a base. A buffer solution is a solution of a weak acid and its conjugate base or solution of a weak base and conjugate acid. The  pH \text{ pH }change of the buffer solution to a very little extent when a small amount of strong acid (like  HCl \text{ HCl } ) and strong bases ( like  NaOH \text{ NaOH } ) is added to it.

Complete step by step answer:
A buffer solution is one that can resist change in it’s  pH \text{ pH } on the addition of an acid or a base.
A very common buffer is prepared by mixing an equimolar aqueous solution of ammonium hydroxide  NH4OH \text{ N}{{\text{H}}_{\text{4}}}\text{OH } and ammonium chloride  NH4Cl \text{ N}{{\text{H}}_{\text{4}}}\text{Cl } . Ammonium hydroxide is slightly dissociated while ammonium chloride  NH4Cl \text{ N}{{\text{H}}_{\text{4}}}\text{Cl } being a strong base salt is almost completely dissociated. The mixture thus contains ammonium hydroxide  NH4OH \text{ N}{{\text{H}}_{\text{4}}}\text{OH } molecules as well as ammonium ion  NH4+ \text{ NH}_{4}^{+}\text{ } and  Cl \text{ C}{{\text{l}}^{-}}\text{ } ions. Let us consider a buffer solution of this mixture.
Suppose a strong base is added to the above mixture of ammonium hydroxide and ammonium chloride. The oxide ion  OH \text{ O}{{\text{H}}^{-}}\text{ } ions are added will be taken up immediately by ammonium ions to form very slightly dissociated NH4OH \text{ N}{{\text{H}}_{\text{4}}}\text{OH }.
 NH4+ + OH  NH4OH \text{ NH}_{4}^{+}\text{ + O}{{\text{H}}^{-}}\text{ }\to \text{ N}{{\text{H}}_{\text{4}}}\text{OH }
Thus the hydroxide ion added is neutralized by the ammonium ion present in the mixture. There is very little change in  pH \text{ pH } of the mixture.
If on the other hand a strong acid is added the  H\text{ }{{\text{H}}^{\text{+ }}} ions added re neutralized by the ammonium hydroxide present in the mixture. The reaction is as follows,
 H+ NH4OH  NH4+ + H2\text{ }{{\text{H}}^{\text{+ }}}+\text{ N}{{\text{H}}_{\text{4}}}\text{OH }\to \text{ NH}_{4}^{+}\text{ + }{{\text{H}}_{\text{2}}}\text{O }
Thus, again there is very little change in the  pH \text{ pH } of the mixture.
Thus in the buffer solution of ammonium hydroxide and ammonium chloride reverse acidity is due to the presence of ammonium ion and reverse alkalinity is due to the presence of ammonium hydroxide.
Thus from the given pair  NH4OH \text{ N}{{\text{H}}_{\text{4}}}\text{OH }and  NH4Cl \text{ N}{{\text{H}}_{\text{4}}}\text{Cl } is a buffer solution.

Hence, (D) is the correct option.

Note: Note that only weak acid or bases and their conjugate base and acid forms buffer solutions. Consider a solution of sodium chloride water. It  pH \text{ pH }is 7. The addition of even 1 m of 1 M  HCl \text{ HCl } solution to one litre of sodium chloride solution lowers the  pH \text{ pH }of solution from 7 to 3.Similarly, the addition of 1 ml of 1 M  NaOH \text{ NaOH } solution to one litre of sodium chloride solution raises the  pH \text{ pH }of the solution from 7 to 11. So there is no little change in  pH \text{ pH }instead of that there is a large difference in pH \text{ pH }. This sodium chloride is not a buffer solution.