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Question: One thousand small water drops of equal radii combine to form a big drop. The ratio of final surface...

One thousand small water drops of equal radii combine to form a big drop. The ratio of final surface energy to the total initial surface energy is

A

1000 : 1

B

1 : 1000

C

10 : 1

D

1 : 10

Answer

1 : 10

Explanation

Solution

As volume remain constant therefore

R=n1/3rR = n ^ { 1 / 3 } r

 surface energy of one big drop  surface energy of n drop =4πR2Tn×4πr2T\frac { \text { surface energy of one big drop } } { \text { surface energy of } n \text { drop } } = \frac { 4 \pi R ^ { 2 } T } { n \times 4 \pi r ^ { 2 } T }

R2nr2=n2/3r2nr2\frac { R ^ { 2 } } { n r ^ { 2 } } = \frac { n ^ { 2 / 3 } r ^ { 2 } } { n r ^ { 2 } }= 1n1/3=1(1000)1/3=110\frac { 1 } { n ^ { 1 / 3 } } = \frac { 1 } { ( 1000 ) ^ { 1 / 3 } } = \frac { 1 } { 10 }