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Question: One solid sphere A and another hollow sphere B are of same mass and same outer radii. Their moment o...

One solid sphere A and another hollow sphere B are of same mass and same outer radii. Their moment of inertia abut their diameters are respectively IA and IB such that:

A

Ia = Ib

B

Ia > Ib

C

Ia < Ib

D

Ia / Ib = da / db.

Where dAd _ { A }and dBd _ { B }are the density of the sphere.

Answer

Ia < Ib

Explanation

Solution

If the mass and radius are equal then moment of inertia of hollow sphere will be more than that of solid sphere.

IA=IBksl=25MR2=0.4MR2I _ { A } = I _ { \mathrm { Bksl } } = \frac { 2 } { 5 } M R ^ { 2 } = 0.4 M R ^ { 2 }

\therefore IA<IBI _ { A } < I _ { B }