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Question

Physics Question on Moment Of Inertia

One solid sphere AA and another hollow sphere BB are of same mass and same outer radii. Their moment of inertia about their diameters are respectively IAI_A and IBI_B such that Where dAd_A and dBd_B are their densities

A

IA=IBI_A = I_B

B

IA>IBI_A > I_B

C

IA<IBI_A < I_B

D

IAIB=dAdB\frac {I_A}{I_B} = \frac {d_A}{d_B}

Answer

IA<IBI_A < I_B

Explanation

Solution

Moment of inertia of a uniform density solid sphere, A=25MR2A = \frac{2}{5}MR^{2} And of hollow sphere B=23MR2B = \frac{2}{3}MR^{2} Since M and R are same, IA<IB.I_{A} < I_{B}.