Question

One requires 0.01 mole of $Na_2CO_3$. Mass of $Na_2CO_3.10 H_2O$ to be taken is

• A. 1.06 g
• B. 2.86 g
• C. 1.80 g
• D. 3.02 g

Answer 1

Answer: (B)

2.86 g

Answer 2

$0.01$ mol of $Na_{2}CO_{3} \equiv 0.01$ mol of $Na_{2}CO_{3}\cdot10H_{2}O$ Molar mass of $Na_{2}CO_{3}\cdot10H_{2}O=46+12+48+180=286\,g\,mol^{-1}$ Mass of $0.01$ mol of $Na_{2}CO_{3}\cdot10\,H_{2}O$ $=2.86\,g$