One of the vertices of the major axis of an ellipse is (1, 1... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

One of the vertices of the major axis of an ellipse is (1, 1) and one of the vertices of its minor axis is (-2, -1). If the centre of the ellipse is (-2, 1), then the equation of the ellipse is

A

$\frac{(x+2)^2}{9}+\frac{(y-1)^2}{4}=1$

B

$\frac{(x+2)^2}{16}+\frac{(y-1)^2}{4}=1$

C

$\frac{(x-2)^2}{9}+\frac{(y+1)^2}{4}=1$

D

$\frac{(x-2)^2}{16}+\frac{(y+1)^2}{4}=1$

E

$\frac{(x+2)^2}{9}+\frac{(y-1)^2}{2}=1$

Answer

$\frac{(x+2)^2}{9}+\frac{(y-1)^2}{4}=1$

Explanation

Solution

The correct option is (A): $\frac{(x+2)^2}{9}+\frac{(y-1)^2}{4}=1$