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Question

Physics Question on Moving charges and magnetism

One of the two identical conducting wires of length LL is bent in the form of a circular loop and the other one into a circular coil of NN identical turns. If the same current is passed in both, the ratio of the magnetic field at the central of the loop (BL)(B_L) to that at the centre of the coil (BC)(B_C) , i.e., RBLBCR \frac{B_L}{B_C} will be

A

1N\frac{1}{N}

B

N2N^2

C

1N2\frac{1}{N^2}

D

NN

Answer

1N2\frac{1}{N^2}

Explanation

Solution

L=2πRL = 2 \pi R L=N×2πrL = N \times2\pi r
R=NrR =Nr
BL=μ0i2RB_{L} = \frac{\mu_{0} i}{2R}