Question

One of the two events must occur. If the chance of one is 2/3 of the other, then odds in favour of the other are

• A. 1 : 3
• B. 3 : 1
• C. 2 : 3
• D. None

Answer 1

Answer: (D)

None

Answer 2

P(1) + P(2) = 1

P(1) = $\frac { 2 } { 3 }$ P(2) Ž $\frac { 2 } { 3 }$P(2) + P(2) = 1

Ž P(2) = $\frac { 3 } { 5 }$ = $\frac { 3 } { 3 + 2 }$

\ odds in favour = 3 : 2