Question

One of the two events must occur. If the chance of one is 2/3 of the other, then odds in favour of other are :

• A. 2 : 3
• B. 1 : 3
• C. 3 : 1
• D. 3 : 2

Answer 1

Answer: (D)

3 : 2

Answer 2

Let p be the probability of other event then probability of first event is = since both events are exclusive so p + $\frac { 2 p } { 3 }$ = 1

Ž p = $\frac { 3 } { 5 }$ odds in favour of other (second)are = 3 : 2