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Question

Physics Question on Motion in a plane

One of the following vector identities which is false will be

A

P→.Q→=Q→.P→\overrightarrow{P}.\overrightarrow{Q}=\overrightarrow{Q}.\overrightarrow{P}

B

P→×Q→=Q→×P→\overrightarrow{P}\times\overrightarrow{Q}=\overrightarrow{Q}\times\overrightarrow{P}

C

P→+Q→=Q→+P→\overrightarrow{P}+\overrightarrow{Q}=\overrightarrow{Q}+\overrightarrow{P}

D

P^+Q^=Q^+P^\hat{P}+\hat{Q}=\hat{Q}+\hat {P}

Answer

P→×Q→=Q→×P→\overrightarrow{P}\times\overrightarrow{Q}=\overrightarrow{Q}\times\overrightarrow{P}

Explanation

Solution

P→×Q→≠Q→×P→\overrightarrow{P} \times \overrightarrow{Q} \neq \overrightarrow{Q} \times \overrightarrow{P} because P→×Q→=−Q→×P→\overrightarrow{P} \times \overrightarrow{Q} = - \overrightarrow{Q} \times \overrightarrow{P}