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Question: One of the diameter of the circle circumscribing the rectangle ABCD is 4y = x + 7. If A and B are th...

One of the diameter of the circle circumscribing the rectangle ABCD is 4y = x + 7. If A and B are the points (–3, 4) and

(5, 4) respectively, then the area of the rectangle is –

A

16

B

32

C

8

D

None of these

Answer

32

Explanation

Solution

AB = 8, M = (1, 4)

Let centre of circle is O(h, k)

Q AB is parallel to X axis

Ž MN is parallel to Y axis

Ž h = 1

Now Q 4y = x + 7 is a diameter

4k = h + 7

4k = 1 + 7

k = 2

Ž O(1, 2)

Ž OM = 2

Ž MN = 4

Area = 8 × 4 = 32