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Question

Chemistry Question on States of matter

One mole of oxygen at 273k273\, k and one mole of sulphur dioxide at 546k546 \,k are taken in two separate containers, then,

A

kinetic energy of O2>O_2 > kinetic energy of SO2SO_2

B

kinetic energy of O2<O_2 < kinetic energy of SO2SO_2

C

kinetic energy of both are equal.

D

None of these

Answer

kinetic energy of O2<O_2 < kinetic energy of SO2SO_2

Explanation

Solution

KE=32RTK E=\frac{3}{2} R T KETK E \propto T KEO2KESO2=TO2TSO2=273546=12\frac{K E_{O_{2}}}{K E_{S O_{2}}}=\frac{T_{O_{2}}}{T_{S O_{2}}}=\frac{273}{546}=\frac{1}{2} KESO2=2KEO2K E_{S O_{2}}=2 K E_{O_{2}} KESO2>2KEO2\therefore K E_{S O_{2}}>2 K E_{O_{2}}