Question

One mole of $O_{2}$ gas having a volume equal to 22.4 litres at $0^{o}C$ and 1 atmospheric pressure in compressed isothermally so that its volume reduces to 11.2 litres. The work done in this process is

• A. $1672.5\mspace{6mu} J$
• B. 1728 J
• C. $- 1728J$
• D. $- 1572.5\mspace{6mu} J$

Answer 1

Answer: (D)

$- 1572.5\mspace{6mu} J$

Answer 2

$W = - \mu RT\log_{e}\frac{V_{2}}{V_{1}} = - 1 \times 8.31 \times (273 + 0)\log_{e}\left( \frac{22.4}{11.2} \right)$

$= - 8.31 \times 273 \times \log_{e}2 = - 1572.5J$ [$\bullet \bullet$ $\log_{e}2 = 0.693$]