Question

One mole of non-ideal gas undergoes a change of state (1.0 atm, 3.0 L, 200 K) to (4.0 atm, 5.0 L, 250 K) with a change in internal energy ($\Delta$U) = 40 L-atm. The change in enthalpy of the process in L-atm ;

• A. 43
• B. 57
• C. 42
• D. None of these

Answer 1

Answer: (B)

57

Answer 2

When both P and V are changing

$\Delta$H = $\Delta$U + $\Delta$ (PV) =$\Delta$U + (P2V2 – P1V1)

= 40 + (20 – 3)= 57 L-atm