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Question

Chemistry Question on Thermodynamics

One mole of monoatomic ideal gas expands adiabatieally at initial temperature T against a constant external pressure of I atm from 1 L to 2 L. Find out the final temperature (R=0.0821atmK1moI1)(R = 0.0821\: atm \: K^{-1}m oI^{-1})

A

T

B

T(2)531\frac{T}{ (2)^{\frac{5}{3}-1}}

C

T23×0.082T -\frac{2}{ 3 \times 0.082}

D

T+23×0.082T + \frac{2}{ 3 \times 0.082}

Answer

T23×0.082T -\frac{2}{ 3 \times 0.082}

Explanation

Solution

In case of reversible thermodynamic process, ?H=nCp?T \, \, \, \, \, \, \, \, \, \, \, ? H = nC_p ? T \therefore \, Process is isothermal, ?T=0?H=0 \, \, \, ? T = 0 \Rightarrow \, ? H = 0