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Question: One mole of ideal monoatomic gas (g = 5/3) is mixed with two mole of diatomic gas (g = 7/5). What is...

One mole of ideal monoatomic gas (g = 5/3) is mixed with two mole of diatomic gas (g = 7/5). What is g for mixture ?

A

3/2

B

2315\frac{23}{15}

C

1913\frac{19}{13}

D

4/3

Answer

1913\frac{19}{13}

Explanation

Solution

gmix = μ1Cp1+μ2Cp2μ1Cv1+μ2Cv2\frac{\mu_{1}C_{p_{1}} + \mu_{2}C_{p_{2}}}{\mu_{1}C_{v_{1}} + \mu_{2}{C_{v}}_{2}}

= (1×52R)+(2×72R)(1×32R)+(2×52R)\frac{\left( 1 \times \frac{5}{2}R \right) + \left( 2 \times \frac{7}{2}R \right)}{\left( 1 \times \frac{3}{2}R \right) + \left( 2 \times \frac{5}{2}R \right)} = 1913\frac{19}{13}