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Question: One mole of ideal monatomic gas (\(\gamma =\)5/3) is mixed with one mole of diatomic gas (\(\gamma=\...

One mole of ideal monatomic gas (γ=\gamma =5/3) is mixed with one mole of diatomic gas (γ=\gamma=7/5). γ\gamma denotes the ratio of specific heat at constant pressure, to that at constant volume. Find γ\gamma for the mixture.
A. 3/2
B. 23/15
C. 35/23
D. 4/3

Explanation

Solution

The degrees of freedom for a monatomic gas is 33 and that for a diatomic gas is 55.
The ratio of specific heats γ\gamma for an ideal gas is
γ=1+2f\gamma =1+\dfrac{2}{f}

Let N1{{N}_{1}} moles of an ideal gas with f1{{f}_{1}} degrees of freedom per molecule be mixed with N2{{N}_{2}} moles of another ideal gas with f2{{f}_{2}} degrees of freedom per molecule at a particular temperature. The ratio of specific heats γ\gamma for the mixture is

γ=N1(2+f1)+N2(2+f2)N1f1+N2f2\gamma =\dfrac{{{N}_{1}}(2+{{f}_{1}})+{{N}_{2}}(2+{{f}_{2}})}{{{N}_{1}}{{f}_{1}}+{{N}_{2}}{{f}_{2}}}

Complete step by step answer:
For the monatomic gas,
Number of moles, N1=1{{N}_{1}}=1
γ=53\gamma =\dfrac{5}{3}
Calculate the degrees of freedom f1{{f}_{1}} of the monatomic gas by substituting the value of γ\gamma in the γ\gamma -ff relation:
\dfrac{5}{3}=1+\dfrac{2}{{{f}_{1}}} \\\
    531=2f1 \implies \dfrac{5}{3}-1=\dfrac{2}{{{f}_{1}}} \\\
    23=2f1 \implies \dfrac{2}{3}=\dfrac{2}{{{f}_{1}}} \\\
    f1=3 \implies {{f}_{1}}=3 \\\

For the diatomic gas,
Number of moles, N2=1{{N}_{2}}=1
γ=75\gamma =\dfrac{7}{5}
Calculate the degrees of freedom f2{{f}_{2}} of the monatomic gas by substituting the value of γ\gamma in the γ\gamma -ff relation:
\dfrac{7}{5}=1+\dfrac{2}{{{f}_{2}}} \\\
    751=2f2 \implies \dfrac{7}{5}-1=\dfrac{2}{{{f}_{2}}} \\\
    25=2f2 \implies \dfrac{2}{5}=\dfrac{2}{{{f}_{2}}} \\\
    f2=5 \implies {{f}_{2}}=5 \\\

Now, substituting the values of N1{{N}_{1}} ,N2{{N}_{2}}and f1{{f}_{1}} ,f2{{f}_{2}} in the formula for the ratio of specific heats γ\gamma for the mixture:

γ=1(2+31)+1(2+5)(1)(3)+(1)(5) \gamma =\dfrac{1(2+{{3}_{1}})+1(2+5)}{(1)(3)+(1)(5)}\\\
    γ=128 \implies \gamma =\dfrac{12}{8} \\\
    γ=32 \implies \gamma =\dfrac{3}{2} \\\

So, the correct answer is “Option A”.

Additional Information:
In monatomic gases, the atoms are not bound to each other and free to move in the three dimensional space. So, they have 3 degrees of freedom (translational). Only noble gases are monatomic at standard temperature and pressure.
In diatomic gases, two atoms are bonded to each other by a rigid bond. They have 5 degrees of freedom (3 translational and 2 rotational). Hydrogen, oxygen, nitrogen, etc exist as diatomic molecules.

Note:
The ratio of specific heats is a constant independent of the temperature. In addition, the expression holds true only for ideal gas mixture.