Question

One mole of ethyl acetate on treatment with an excess of $LiAlH_{4}$ in dry ether and subsequent acidification produces

• A. 1 mol acetic acid +1 mol ethyl alcohol
• B. 1 mol ethyl alcohol + 1mol methyl alcohol
• C. 2 moles of ethyl alcohol
• D. 1 mol of 2-butanol.

Answer 1

Answer: (C)

2 moles of ethyl alcohol

Answer 2

$\underset{Ethylacetate}{CH_{3}COOC_{2}H_{5}}\underset{orH_{2}/Pt}{\overset{\quad LiAlH_{4}/H_{3}O^{+}\quad}{\rightarrow}}CH_{3}CH_{2}OH + C_{2}H_{5}OH$