Question

One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27^o C. If the work done during the process is 3 kJ, the final temperature will be equal to $(C_{v} = 20JK^{- 1})$

• A. 150 K
• B. 100 K
• C. 26.85 K
• D. 295 K

Answer 1

Answer: (A)

150 K

Answer 2

Work done during adiabatic expansion =$\mathbf{C}_{\mathbf{v}}\mathbf{(}\mathbf{T}_{\mathbf{2}}\mathbf{-}\mathbf{T}_{\mathbf{1}}\mathbf{)}$

$\mathbf{- 3000 = 20(}\mathbf{T}_{\mathbf{2}}\mathbf{- 300)}$ or $T_{2} = 150K$.