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Chemistry Question on internal energy

One mole of an ideal gas at 300 K is expanded isothermally from an initial volume of 1 litre to 10 litres. Then ΔS(cal deg−1 mol−1) {\Delta S (cal \, deg^{-1} \, mol^{-1})} for this process is : (R=2 cal K−1 mol−1) { (R = 2 \, cal \, K^{-1} \, mol^{-1})}

A

7.12

B

8.314

C

4.6

D

3.95

Answer

4.6

Explanation

Solution

For an isothermal process Δ=2.303 nR log⁡V2V1\Delta = 2.303 \, nR \, \log \frac{V_2}{V_1} =2.303×1×2log⁡101 = 2.303 \times 1 \times 2 \log \frac{10}{1} =4.6  deg−1 mol−1 = 4.6 \, \cal \, deg^{-1} \, mol^{-1}