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Question: One mole of an ideal diatomic gas is taken through the cycle as shown in the figure: \[1 \to 2\]:...

One mole of an ideal diatomic gas is taken through the cycle as shown in the figure:
121 \to 2: isochoric process
232 \to 3: a straight line of P-V diagram
313 \to 1: isobaric process

The average molecular speed of the gas in the states 1, 2 and 3 in the ratio:

A. 1:2:21:2:2
B. 1:2:21:\sqrt 2 :\sqrt 2
C. 1:1:11:1:1
D. 1:2:41:2:4

Explanation

Solution

In 121 \to 2, Pressure is directly proportional to temperature. In 313 \to 1, Volume is directly proportional to Temperature. And the average molecular speed (Vrms)\left( {{V_{rms}}} \right) is directly proportional to RTM\sqrt {\dfrac{{RT}}{M}} , hence vTv \propto \sqrt T

Complete step by step answer:
In the state 1
Let temperature be To{T_o}
and we know that, PV=nRTPV = nRT
In the state 2
Since 121 \to 2 is an isochoric process
Hence, in State 1
PT=\dfrac{P}{T} = Constant
vT0v \propto {T_0}
when Pressure is equal to 4Po4{P_o}. Thus, the Temperature =4To = 4{T_o}

State 3
Since 313 \to 1 is an isobaric process,
According to Charlee’s law
VTV \propto T
VT=\dfrac{V}{T} = Constant
When Volume is 4Vo4{V_o}. Thus Temperature =4To = 4{T_o}

The root-mean-square speed or the average molecular speed (Vrms)\left( {{V_{rms}}} \right) is directly proportional to RTM\sqrt {\dfrac{{RT}}{M}}
vT\Rightarrow v \propto \sqrt T
The average velocity of the gas molecule has the formula : ​Vavg=8RTM{V_{avg}} = \sqrt {\dfrac{{8RT}}{M}}
Where,
V= molecular speed of the particle
T = Temperature in Kelvin
M = molar mass of the compound
R = Ideal gas constant

Hence,
State 1, vT0v \propto {T_0}
State 2, v4To=2Tov \propto \sqrt {4{T_o}} = 2\sqrt {{T_o}}
State3, v4To=2Tov \propto \sqrt {4{T_o}} = 2\sqrt {{T_o}}
Hence, V1:V2:V3=To:4To:4YTo{V_1}:{V_2}:{V_3} = \sqrt {{T_o}} :\sqrt {4{T_o}} :\sqrt {4Y{T_o}}
Ratio =1:2:2 = 1:2:2

Therefore, the correct answer is option (A).

Note: Isobaric process is carried out at a constant pressure. In such a process dP=0dP = 0. Isochoric process is a process in which the volume of the system remains constant, whereby dV=0dV = 0. According to the Kinetic Molecular Theory of Gases, the molecular speed of the gas explains that gas particles are in continuous motion and they exhibit ideally elastic collisions.