Question

One mole of a perfect gas expands isothermally to ten times of its original volume. The change in entropy is

• A. 0.1 R
• B. 2.303 R
• C. 10.0 R
• D. 100.0 R

Answer 1

Answer: (B)

2.303 R

Answer 2

$\Delta S= 2.303\, n R \log \frac{V_{2}}{V_{1}} n=1$
$\therefore \Delta S=2.303 R \log \frac{10}{1} \Delta S=2.303\, R$
$(\because \log 10=1)$