Question
Question: One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) ®( 4.0 atm, 5.0 L, 2...
One mole of a non-ideal gas undergoes a change of state (2.0
atm, 3.0 L, 95 K) ®( 4.0 atm, 5.0 L, 245 K)
With a change in internal energy DE = 30 L atm. The change in enthalpy (DH) in the process in L-atm is-
A
40.0
B
42.3
C
44.0
D
Not defined, because pressure is not constant
Answer
44.0
Explanation
Solution
DH = DE + D(PV) = DE + (P2V2 – P1V1)
or DH = 30 + (20 – 6) = 30 + 14 = 44 Latm.