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Question: One mole of a gas filled in a container at N.T.P., the number of molecules in 1 cm<sup>3</sup> of vo...

One mole of a gas filled in a container at N.T.P., the number of molecules in 1 cm3 of volume will be

A

6.02×1023/224006.02 \times 10^{23}/22400

B

6.02×10236.02 \times 10^{23}

C

1/22400

D

6.02×1023/766.02 \times 10^{23}/76

Answer

6.02×1023/224006.02 \times 10^{23}/22400

Explanation

Solution

Number of molecule in 22.4 litre gas at N.T.P.

=6.023×1023= 6.023 \times 10^{23}

or number of molecule in 22.4×103cm3=6.023×102322.4 \times 10^{3}cm^{3} = 6.023 \times 10^{23} [As 22.4 litre =22.4×103cm3= 22.4 \times 10^{3}cm^{3}]

∴ Number of molecules in 1cm3=6.023×1023224001cm^{3} = \frac{6.023 \times 10^{23}}{22400}.