Question

One mole of 1,2-dibromopropane on treatment with x moles of $\mathrm { NaNH } _ { 4 }$ followed by treatment with ethyl bromide gave a 2-pentyne. The value of x is

• A. One
• B. Two
• C. Three
• D. Four

Answer 1

Answer: (C)

Three

Answer 2

: $\mathrm { CH } _ { 3 } \mathrm { CH } ( \mathrm { Br } ) \mathrm { CH } _ { 2 } ( \mathrm { Br } ) \xrightarrow { 2 \mathrm { NaNH } _ { 2 } } \mathrm { CH } _ { 3 } - \underset { \downarrow \mathrm { NsNH } _ { 2 } } { \equiv } \equiv \mathrm { CH }$

Total number of moles of $\mathrm { NaNH } _ { 2 } = 2 + 1 = 3$