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Question: One milligram of matter is converted into energy. The energy released will be: A. \(9 \times {10^6...

One milligram of matter is converted into energy. The energy released will be:
A. 9×106 J9 \times {10^6}\,J
B. 9×108 J9 \times {10^8}\,J
C. 9×1010 J9 \times {10^{10\,}}J
D. 9×1012 J9 \times {10^{12}}\,J

Explanation

Solution

Here we have to use the Einstein-mass energy relation to get the answer.
Einstein's condition E=mc2E = m{c^2} shows that energy and mass are exchangeable. The hypothesis of special relativity clarifies how space and time are connected for objects that are moving in a uniform motion. One of its most specific angles concerns objects moving at the speed of light.

Complete step by step answer:
This condition E=mc2E = m{c^2} additionally shows that mass speeds up, which adequately sets a speed boundary for how quick things can move known to man. Basically, the speed of light (c) is the quickest speed at which an item can go in a vacuum. As an item moves, its mass likewise increments. Close to the speed of light, the mass is high to the point that it arrives at infinity, and would require unbounded energy to move it, along these lines covering how quick an object can move.
An extraordinary circumstance known to man of the little, called "quantum entanglement," is confounding on the grounds that it appears to include quantum particles interfacing with one another at speeds quicker than the speed of light. In particular, estimating the property of one particle can quickly reveal to you the property of another molecule, regardless of the distance away they are.
First let us convert the mass one milligram to kilogram:
m=1 mg =1×10−3 g =1×10−6  kg  m = 1\,mg \\\ = 1 \times {10^{ - 3}}\,g \\\ = 1 \times {10^{ - 6\,}}\,kg \\\
The speed of light is given by:
c=3×108 ms−1c = 3 \times {10^8}\,m{s^{ - 1}}

Putting the values in the mass energy equation we get:
E=mc2 =1×10−6 kg×(3×108 ms−1)2 =9×1010 J  E = m{c^2} \\\ = 1 \times {10^{ - 6}}\,kg \times {\left( {3 \times {{10}^8}\,m{s^{ - 1}}} \right)^2} \\\ = 9 \times {10^{10}}\,J \\\ .

So, the correct answer is “Option C”.

Note:
Here we have to first convert the units to SI units. Only then we can get the correct answer.
Also we have to remember the mass energy relation.
The main explanation is that light moves at the speed it does on the grounds that photons, the quantum particles that make up light, have a mass of zero.